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Lemma nondecreasing_right_continuousP now has e: {posnum R} #764

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hoheinzollern
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@hoheinzollern hoheinzollern commented Oct 7, 2022

This addresses @zstone1's comment in #677

@hoheinzollern hoheinzollern mentioned this pull request Oct 7, 2022
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(f : cumulative R) :
e > 0 -> exists d : {posnum R}, f (a + d%:num) <= f a + e.
exists d : {posnum R}, f (a + d%:num) <= f a + (e%:num).
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Suggested change
exists d : {posnum R}, f (a + d%:num) <= f a + (e%:num).
exists d : {posnum R}, f (a + d%:num) <= f a + e%:num.

@CohenCyril
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CohenCyril commented Oct 10, 2022

The current phrasing is already good. (cf #677 (comment))

@CohenCyril CohenCyril closed this Oct 10, 2022
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3 participants